Arrays Ionic
Dec/100
atomic stufffff?
The crystal structure of an ionic compound consists of alternating cations and anions lying next to each other in three dimensions. If the cation radius is 53.8% of the anion radius and the distance between the cation nuclei is 580. pm, WHAT ARE THE RADII OF THE ANION AND CATION?
(Note: This ionic compound is a three dimensional array. The cation to cation, center-to-center distance specified is through the center of the anion.)
This is just a system of two equations:
1. r(c) + r(a) = 580. where r(c) and r(a) are cation and anion radii, respectively
2. r(c) = 0.538*r(a).
Substituting r(c) in eq1 with eq2 we will get: 0.538*r(a) + r(a) = 580 => r(a) = 377.1 pm. From here we can get to r(c):
r(c) = 0.538*r(a) = 202.9pm
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